Question 190-1 : A straight line drawn on a chart measures 463 cm and represents 150 nm the chart scale is ? [ Level reports ]

Question 190-2 : On a polar stereographic chart the initial great circle course from a 70°n 060°w to b 70°n 060°e is approximately ?

030° t .

1386conversion angle formula is not accurate for long distancesbut we can try conversion angle 12 g sin lmg change of longitude 120° lm = mean latitude 70° conversion angle = 12 x 120 x sin70 = 56°090° rhumb line 56° = 034°

Question 190-3 : On a lambert conformal conic chart great circles that are not meridians are ?

Curves concave to the parallel of origin.

The parallel of origin is approximately at half way between the two standard parallels 1387 1388standard parallels are 20°n and 50°n parallel of origin is 30°nmeridians which are great circles are straight linesall other great circles are curved concave to the parallel of origin 2506

Question 190-4 : On a direct mercator projection at latitude 45° north a certain length represents 70 nm at latitude 30° north the same length represents approximately ?

86 nm.

60 x cos 45 x x = 704242 x x = 70 x = 70 4242 = 16560 x cos 30 x 165 = 86 nm ducksherminator i'd just like to give the method i used to find the answer i personnaly find it easier 70cos45° x cos30° = 8573

Question 190-5 : On a polar stereographic projection chart showing the south pole a straight line joins position a 70°s 065°e to position b 70°s 025°w the true course on departure from position a is approximately ?

225°.

Draw the situtation 1389

Question 190-6 : On a direct mercator projection the distance measured between two meridians spaced 5° apart at latitude 60°n is 8 cm the scale of this chart at latitude 60°n is approximately ?

1 3 500 000.

Scale = chart lenghtearth distanceearth distance = 5° x 60 nm x cos 60° = 150 nm150 nm x 1852 = 2778 km1 cm chart scale = 2778 8 = 34725 km1 cm 3 472 000 cm

Question 190-7 : Two positions plotted on a polar stereographic chart a 80°n 000° and b 70°n 102°w are joined by a straight line whose highest latitude is reached at 035°wat point b the true course is ?

203°.

Draw the situation 1391at the highest latitude 035°w our true course is 270°on a polar stereographic chart convergency is equal to the change of longitude 102° 35° = 67°270° 67° = 203°

Question 190-8 : Assume a north polar stereographic chart whose grid is aligned with the greenwich meridianan aircraft flies from the geographic north pole for a distance of 480 nm along the 110°e meridian then follows a grid track of 154° for a distance of 300 nm its position is now approximately 2514 ?

80°00'n 080°e.

The grid is aligned with the greenwich meridianuse meridian 090°e graduation to find distance 480 nm along the 110°e 1° = 60 nm 48060 = 8°next step your aircraft turn on a 154° heading grid track for a distance of 300 nm 30060 = 5° 1397its position is now approximately 80°00'n 080°e

Question 190-9 : The convergence factor of a lambert conformal conic chart is quoted as 078535 at what latitude on the chart is earth convergency correctly represented ?

51°45'.

The convergency factor on a lambert chart is the sinus of the parallel of origin n = sin l0 078535 = sin parallel of originparallel of origin = sin 1 078535 = 5175 51°45'

Question 190-10 : At 47° north the chart distance between meridians 10° apart is 127 cm the scale of the chart at 47° north approximates ?

1 6 000 000.

Scale = chart lenghtearth distanceearth distance = 10° x 60 nm x cos 47° = 4092 nm4092 x 1852 = 758 km1 cm chart scale = 758 127 = 60 km1 cm 6 000 000 cm marcinkocybik why we substract 758 127 we divide because 127 cm on the chart corresponds to 758 km on earth and we want to now the value for 1 cm

Question 190-11 : On a direct mercator chart a great circle will be represented by a ?

Curve concave to the equator.

On a direct mercator chart meridians a parallel equally spaced vertical straight lines com encom061 514jpggreat circle is the shortest distance between two points on earth but not on a direct mercator chartfor information com encom061 394bjpg

Question 190-12 : The constant of cone of a lambert conformal conic chart is quoted as 03955 at what latitude on the chart is earth convergency correctly represented ?

23°18'.

Question 190-13 : On a lambert conformal chart the distance between meridians 5° apart along latitude 37° north is 9 cm the scale of the chart at that parallel approximates ?

1 5 000 000.

Scale = chart lenghtearth distanceearth distance = 5° x 60 nm x cos 37° = 2396 nm2396 x 1852 = 444 km1 cm chart scale = 444 9 = 4933 km1 cm 4 933 000 cm

Question 190-14 : The great circle bearing from a 70°s 030°w to b 70°s 060°e is approximately ?

132° t .

1422great circle direction at a = 090° rhumb line + conversion angle 12 g sin lm conversion angle = 12 g sin lmg change of longitude 90° lm = mean latitude 70° conversion angle = 12 x 90° x sin70°conversion angle = 42°great circle direction at a = 090° + 42° = 132°

Question 190-15 : In a navigation chart a distance of 49 nm is equal to 7 cm the scale of the chart is approximately ?

1 1 300 000.

49 nm x 1852 = 91 km91 7 = 13 km1 cm 1 300 000 cm

Question 190-16 : At 60°n the scale of a direct mercator chart is 1 3 000 000 what is the scale at the equator ?

1 6 000 000.

Scale at 60°n = scale at equator x 1cos60° = 13 000 000scale at equator = cos60°3 000 000scale at equator = 16 000 000

Question 190-17 : What is the chart distance between longitudes 179°e and 175°w on a direct mercator chart with a scale of 1 5 000 000 at the equator ?

133 mm.

Scale = chart distanceearth distanceearth distance = 6º = 6° x 60 nm = 360 nm at the equator360 nm = 6673km = 667 300 000 mmscale = chart distance 667 300 000 = 15 000 000chart distance = 667 300 000 5 000 000 = 133 mm dalton on a mercator chart 179e and 175w are not distant by 6° but by 179+175=354° earth is a globe longitudes 179°e and 175°w are separated by 354° or 6°

Question 190-18 : The total length of the 53°n parallel of latitude on a direct mercator chart is 133 cm what is the approximate scale of the chart at latitude 30°s ?

1 26 000 000.

On a direct mercator chart meridians are parallel so all parallels of latitude will have the same lenghtscale = chart distance earth distance scale = 133 cm 360 x 60 x cos30°scale = 133 cm 18706 nm = 133 cm 346435 kmscale = 133 cm 34 643 500 mscale = 133 cm 34 643 500 000 cm1 cm 26 047 744 cm

Question 190-19 : A lambert conformal conic projection with two standard parallels ?

The scale is only correct along the standard parallels.

The lambert conformal is what most of today's aeronautical charts are based on 1776on a lamberts chart scale is only correct at the standard parallels where the cones slices through the surface of the globe and convergency is correct along the parallel of origin and the constant of the cone or convergence factor is the sine of the parallel of origin

Question 190-20 : The constant of the cone on a lambert chart where the convergence angle between longitudes 010°e and 030°w is 30° is ?

075.

Chart convergency = difference of longitude x constant of conedifference of longitude = 10°e to 30°w = 40°30° = 40° x constant of coneconstant of cone = 3040 = 075

Question 190-21 : A line drawn on a chart which joins all points where the value of magnetic variation is zero is called an ?

Agonic line.

com encom061 87jpgagonic line a line which joins all points where the value of magnetic variation is zero

Question 190-22 : The chart distance between meridians 10° apart at latitude 65° north is 95 cm the chart scale at this latitude approximates ?

1 5 000 000.

Scale = chart lenghtearth distanceearth distance = 10° x 60 nm x cos 65° = 254 nm254 x 1852 = 470 km1 cm chart scale = 470 95 = 4947 km1 cm 4 947 000 cm

Question 190-23 : On a lambert conformal conic chart with two standard parallels the quoted scale is correct ?

Along the two standard parallels.

The lambert conformal is what most of today's aeronautical charts are based on 1776on a lamberts chart scale is correct at the standard parallels where the cones slices through the surface of the globe and convergency is correct along the parallel of origin and the constant of the cone or convergence factor is the sine of the parallel of origin

Question 190-24 : On a lambert conformal conic chart earth convergency is most accurately represented at the ?

Parallel of origin.

The lambert conformal is what most of today's aeronautical charts are based on 1776on a lamberts chart scale is correct at the standard parallels where the cones slices through the surface of the globe and convergency is correct along the parallel of origin and the constant of the cone or convergence factor is the sine of the parallel of originconvergency is the angle of inclination between two selected meridians measured at a given latitude

Question 190-25 : A chart has the scale 1 1 000 000 from a to b on the chart measures 38 cm the distance from a to b in nm is ?

205.

1 cm = 1 000 000 = 10 km38 x 10 km = 38 km38 1852 = 205 nm

Question 190-26 : Contour lines on aeronautical maps and charts connect points ?

Having the same elevation above sea level.

Question 190-27 : A rhumb line is ?

A line on the surface of the earth cutting all meridians at the same angle.

com encom061 101jpgremember rhumb lines or loxodromes are tracks of constant true coursegreat circle is the shortest distance between two points

Question 190-28 : A straight line on a lambert conformal projection chart for normal flight planning purposes ?

Is approximately a great circle.

Meridians which are great circles are straight lines all other great circles are almost straight lines but curved concave to the parallel of origin rhumb lines loxodromes are curves concave to the pole

Question 190-29 : An aircraft flies a great circle track from 56°n 070°w to 62°n 110°e the total distance travelled is ?

3720 nm.

070°w to 180°we = 110°180°we to 110°e = 70°difference of longitude = 180°it seems that this great circle track will pass by the north pole from position 56°n 070°w we have 34° of latitude to reach the north pole from north pole to position 62°n 110°e we have 28° of latitude34° + 28° = 62°62° x 60 nm = 3720 nm

Question 190-30 : Parallels of latitude on a direct mercator chart are ?

Parallel straight lines unequally spaced.

1753 direct mercator chart parallels of latitude on a direct mercator chart are parallel straight lines unequally spaced the distance between latitudes increases away from the centremeridians are parallel equally spaced vertical straight lines

Question 190-31 : The parallels on a lambert conformal conic chart are represented by ?

Arcs of concentric circles.

The lambert conformal is what most of today's aeronautical charts are based on com encom061 699jpg

Question 190-32 : Approximately how many nautical miles correspond to 12 cm on a map with a scale of 1 2 000 000 ?

130.

12 cm x 2 000 000 cm = 24 000 000 cm24 000 000 cm = 240 km240 km 1852 = 130 nm

Question 190-33 : A lambert conformal conic chart has a constant of the cone of 075the initial course of a straight line track drawn on this chart from a 40°n 050°w to b is 043° t at acourse at b is 055° t what is the longitude of b ?

034° w.

Convergency = 055° 043° = 12°change in longitude = convergency nchange in longitude = 12° 075 = 16°a is at 050°w and b 34°w 50° 16° minus 16° because we are heading east

Question 190-34 : A lambert conformal conic chart has a constant of the cone of 080a straight line course drawn on this chart from a 53°n 004°w to b is 080° at acourse at b is 092° t what is the longitude of b ?

011°e.

Sin l0 = x gsin l0 = 080x = 80° 92°= 12°g = 12° 080 = 15°15° 4° = 11°

Question 190-35 : What is the radial and dme distance from bel vordme n54397 w006138 to position n5410 w00710 err a 061 241 ?

236° 44 nm.

Question 190-36 : What is the radial and dme distance from bel vordme n54397 w006138 to position n5440 w00730 err a 061 242 ?

278° 44 nm.

Plot position n5440 w00730 and draw a line from belfast vorcenter your protractor you read 278° com encom061 242jpguse the latitude scale to find 44 nm

Question 190-37 : What is the average track °m and distance between wtd ndb n52113 w007050 and ker ndb n52109 w009315 err a 061 244 ?

278° 90 nm.

Img com encom061 244jpgalign your protractor with the average magnetic north between wtd and ker magnetic track is 278°use the latitude scale to find the distance 90 nm

Question 190-38 : What is the average track °m and distance between crn ndb n53181 w008565 and wtd ndb n52113 w007050 err a 061 246 ?

142° 95 nm.

Report the magnetic north tick from cml clonmel ndb center your protractor you read an average magnetic trak of 142° com encom061 246jpguse the scale to find the distance 95 nm

Question 190-39 : What is the average track °m and distance between ker ndb n52109 w009315 and crn ndb n53181 w008565 err a 061 248 ?

025° 70 nm.

com encom061 248pnguse the vertical scale to find the distance 70 nm magnetic north is indicated over vors and ndbs report a magnetic north tick center your protractor you read an average magnetic track of 025°

Question 190-40 : On a direct mercator chart at latitude 15°s a certain length represents a distance of 120 nm on the earththe same length on the chart will represent on the earth at latitude 10°n a distance of ?

1223 nm.

At latitude 15° 120 nmat latitude 10° cos 10 cos 15 x 120 = 1223 nmsimilar solution lenght at the equator 120 nm cos15 = 12423nmlenght at 10° of latitude 12423 x cos10 = 12234