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Question 281-1 : True airspeed tas is ? [ Attainment AIM ]

Lower than the indicated airspeed ias at altitudes below sea level under isa conditions

Question 281-2 : Total pressure is rho = density ?

Static pressure plus dynamic pressure.

exemple 385: Static pressure plus dynamic pressure
Static pressure minus dynamic pressure. ½ rho v². measured at a small hole in a surface, parallel to the local stream.

Question 281-3 : The unit of measurement for density is ?

Kgm³.

exemple 389: Kgm³
Psi. kg/cm². bar.

Question 281-4 : The transition point is the point where ?

The boundary layer changes from laminar to turbulent.

exemple 393: The boundary layer changes from laminar to turbulent
The velocity of the relative airflow is reduced to zero. changes in lift due to variations in angle of attack are constant. the aeroplane becomes longitudinally unstable when the cg is moved beyond it in an aft direction.

Question 281-5 : Considering a positively cambered aerofoil section the pitching moment when the lift coefficient cl=0 is ?

Negative nose down .

When a positively cambered airfoil is at zero lift it has to be at a small negative alpha to cancel out the camber which gives some lift at zero alpha the angle of attack has a negative value when the lift coefficient equals zero it is because the pressure distribution is producing negative lift at the front and positive lift at the back of the airfoil 1631a symmetrical aerofoil need to have a positive pitch to produce lift if the pitching moment is zero the lift is zeroa positively cambered aerofoil produces lift with a zero pitching moment thus not to produce lift it need a negative pitching moment 2416in this example lift coeffient = 0 when angle of attack = 4° the pitching moment is nose down
exemple 397: Negative nose down
Equal to zero. maximum. positive (nose up).

Question 281-6 : An aerofoil is cambered when ?

The line which connects the centres of all inscribed circles is curved.

exemple 401: The line which connects the centres of all inscribed circles is curved
The chord line is curved. the upper surface of the aerofoil is curved. the maximum thickness is large compared with the length of the chord.

Question 281-7 : A flat plate when positioned in the airflow at a small angle of attack will produce ?

Both lift and drag.

exemple 405: Both lift and drag
Lift but no drag. drag but no lift. neither lift nor drag.

Question 281-8 : Positive static stability of an aeroplane means that following a disturbance from the equilibrium condition ?

The initial tendency is to return towards its equilibrium condition.

exemple 409: The initial tendency is to return towards its equilibrium condition
The initial tendency is to diverge further from its equilibrium condition. the tendency is to move with an oscillatory motion of decreasing amplitude. the tendency is to move with an oscillatory motion of increasing amplitude.

Question 281-9 : Load factor is ?

Liftweight.

exemple 413: Liftweight
Weight/lift. 1/bank angle. wing loading.

Question 281-10 : Which statement is correct about an expansion wave in supersonic flow 1 the static temperature in front of an expansion wave is higher than the static temperature behind it2 the speed in front of an expansion wave is higher than the speed behind it ?

1 is correct and 2 is incorrect.

The effect on pressure temperature density and velocity is the opposite in expansion waves to obliquenormal shock waves expansion wave also known as a prandtl meyer expansion fan when a supersonic airflow passes over a surface that suddenly drops away or rounds corner an expansion fan of an infinite number of shock waves forms at the apex of the corner and diverts the airflow around the cornerairflowing through an expansion fan goes through the following changes 1the airsteam accelerates and the air behind the shock wave has higher supersonic velocity2the airflow direction follows the surface contour3the static pressure behind the expansion wave decreases4the density behind the expansion wave decreases5there is no loss of energy 2417 obliquenormal wave 2418
exemple 417: 1 is correct and 2 is incorrect
1 and 2 are correct. 1 is incorrect and 2 is correct. 1 and 2 are incorrect.

Question 281-11 : Which rotor system is most effective in terms of control power ?

The rigidhead.

2405
exemple 421: The rigidhead
The teetering head. the semi-rigid head. the fully articulated head.

Question 281-12 : What happens as a helicopter accelerates through 12 kt ?

It passes through translational lift.

exemple 425: It passes through translational lift
It passes through tail rotor drift. it decends unless corrected. it yaws towards the retreating blade.

Question 281-13 : With reference to translational lift which of the following statements is true ?

Translational lift with associated reduction in induced flow and inflow angle becomes effective at about 12 knots.

Question 281-14 : When a helicopter is in an ideal free air hover the trt is acting vertically and is equal and opposite to ?

Weight and parasite drag.

Trt total rotor thrustthe parasite drag comes from the airflow blowing downwards over the fuselage it adds to the apparent weight so you need a little extra thrust to overcome itlooking at forward flight you have four main vectors 2419as you slow down and the downwash slowly changes from being rear and down to just being down the vectors move around a little lift and weight stay the same drag moves to being a bit down and thrust has to move a bit upin the hover weight and drag coincide and lift and thrust coincide so in the hover you get lift + thrust = weight + drag
exemple 433: Weight and parasite drag
Weight and rotor drag. parasite drag and rotor drag. engine torque and rotor drag.

Question 281-15 : As a helicopter accelerates the attitude becomes ?

Nose down.

exemple 437: Nose down
Nose up. level. rolls towards the advancing side.

Question 281-16 : Where on the surface of a typical aerofoil will flow separation normally start at high angles of attack ?

Upper side trailing edge.

Question 281-17 : Lift is the ?

Component of the total aerodynamic force perpendicular to the undisturbed airflow.

The component of the force perpendicular to the relative free stream ie undisturbed airflow is lift
Vertical component of the total aerodynamic force, perpendicular to the undisturbed airflow. component of the total aerodynamic force, perpendicular to the local flow. component of the total aerodynamic force, perpendicular to the mean aerodynamic chord.

Question 281-18 : A helicopter is statically stable when it shows the ?

Tendency to return to its original attitude after having been displaced.

exemple 449: Tendency to return to its original attitude after having been displaced
Tendency to pitch up at low airspeed ability to resist dynamic roll-over tendency to pitch down at low airspeed

Question 281-19 : Blade sailing can occur when ?

The rotor is starting up or slowing down in gusty wind conditions.

exemple 453: The rotor is starting up or slowing down in gusty wind conditions
The rotor rpm is too high the helicopter is facing out of wind with rotor rpm too high entering autorotation with the rotor rpm too low

Question 281-20 : Which statement is correct regarding the coning angle ?

With increased rotor rpm the coning angle decreases.

Question 281-21 : Dissymmetry of lift due to forward flight is compensated for by the ?

Advancing blade flapping up and reducing its angle of attack and the retreating blade flapping down and increasing its angle of attack.

exemple 461: Advancing blade flapping up and reducing its angle of attack and the retreating blade flapping down and increasing its angle of attack
Advancing blade flapping up and increasing its angle of attack and the retreating blade flapping down and reducing its angle of attack movement of the cyclic pitch to balance dissymmetry drag hinge allowing the advancing blade to lag, reducing its relative airspeed while increasing the relative airspeed of the retreating blade

Question 281-22 : The rotor disc plane is always ?

Perpendicular to the rotor thrust.

exemple 465: Perpendicular to the rotor thrust
Perpendicular to the main rotor shaft parallel to the plane of the swash plate parallel to the relative airflow

Question 281-23 : The main induced air flow velocity is considered perpendicular to the ?

Tip path plane.

Question 281-24 : For a rotor which turns in a clockwise direction seen from above in a backward flight with zero wind the pilot will have the advancing blade ?

On his right.

exemple 473: On his right
In front of him on his left behind him

Question 281-25 : For a rotor which turns in an anti clockwise direction seen from above in a backward flight with zero wind the pilot will have the retreating blade ?

On his right.

exemple 477: On his right
On his left behind him in front of him

Question 281-26 : For a rotor which turns in a clockwise direction seen from above in a backward flight with zero wind the pilot will have the retreating blade ?

On his left.

exemple 481: On his left
On his right in front of him behind him

Question 281-27 : Separation of the airflow from a blade ?

Occurs with increasing mach number at decreasing angle of attack.

exemple 485: Occurs with increasing mach number at decreasing angle of attack
Occurs with decreasing mach number at decreasing angle of attack. occurs at a constant angle of attack. always occurs at the same speed.

Question 281-28 : Drag dampers in a rotor system ?

May use the principle of damping by friction.

exemple 489: May use the principle of damping by friction
May be used on teetering rotors. ensure that the centre of gravity of the blades coincides always with the axis of rotation. counteract the coriolis forces on the individual blades.

Question 281-29 : The main reason for the negative range of tail rotor pitch is ?

For yaw control in autorotation.

exemple 493: For yaw control in autorotation
To counteract tail rotor drift. to eliminate tail rotor flapping. to counteract tail rotor roll.

Question 281-30 : Why is sweep back often applied to the tip of modern rotor blades ?

To reduce the mach effects on the advancing blade.

exemple 497: To reduce the mach effects on the advancing blade
To reduce the compressibility effects on the retreating blade. to reduce the loss of thrust when hovering. to reduce the susceptibility to crosswind during forward flight.

Question 281-31 : One reason for increased rotor rpm in the flare is ?

Conservation of angular momentum coriolis effect.

exemple 501: Conservation of angular momentum coriolis effect
Too much anti-torque pedal movement insufficient anti-torque pedal movement increased moment of inertia

Question 281-32 : The advance angle is ?

Used to compensate for phase lag.

exemple 505: Used to compensate for phase lag
Used to decrease control forces. another expression for the delta three angle. used to compensate for tail rotor drift.

Question 281-33 : The ground effect is affected by 1 the hover height2 the length of the helicopter3 the ground texture4 the diameter of the main rotorthe combination of correct statements is ?

1 3 and 4.

exemple 509: 1 3 and 4
1, 2 and 4. 2, 3 and 4. 1, 2, 3 and 4.

Question 281-34 : As a result of a positive 'g' manoeuvre in a helicopter there is ?

An increase in coning angle.

exemple 513: An increase in coning angle
A decrease in coning angle. no effect in coning angle. an increase or a decrease in coning angle, depending on the direction of rotation of the main rotor.

Question 281-35 : Drag dampers in a rotor system ?

May use the principle of damping by means of oil.

exemple 517: May use the principle of damping by means of oil
Are adjustable for the purpose of blade-tracking. can be left out on fully articulated rotor systems depending on the number of blades. restrict the coriolis forces on the rotor blades.

Question 281-36 : The forces and moments caused by the dragging of the rotor blades on a hingeless rotor head are absorbed ?

Through bending at the blade root.

exemple 521: Through bending at the blade root
By the use of drag hinges. by the blade pitch bearing. through bending of the rotor mast.

Question 281-37 : The recommended recovery action from vortex ring settling with power is to ?

Cyclic forward to increase airspeed pause for airspeed then apply power.

exemple 525: Cyclic forward to increase airspeed pause for airspeed then apply power
Cyclic forward to increase airspeed whilst applying more power lower collective lever no action is necessary

Question 281-38 : The centre of gravity of a single rotor helicopter will be ?

Close to the main rotor axis.

exemple 529: Close to the main rotor axis
Directly below the rotor head whenever the helicopter is in flight, due to 'pendulum' effect. defined by the landing gear layout. equidistant between the main axis and the tail rotor.

Question 281-39 : Drag damping may be achieved by means of ?

Oil or mechanical friction.

exemple 533: Oil or mechanical friction
Gas. adding masses in the blade tips. coil springs.

Question 281-40 : With regard to an intermeshing rotor helicopter synchropter i the full power available can be used for liftingii this helicopter has good directional stability ?

I true ii false.

1349you do not have to counteract a torque reaction on a synchropter the two rotors turn in opposite directions this arrangement allows the helicopter to function without the need for a tail rotor which saves power however neither rotor lifts directly vertically which reduces efficiencyyaw is accomplished through varying torque which is done simply by increasing collective pitch on one of the blade sets directional stability is not optimal
exemple 537: I true ii false
I true, ii true. i false, ii true. i false, ii false.



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