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Refer to figure 031 59 .the see saw is in a state of equilibrium calculate the ? [ Result topography ]

Question 86-1 : 30 49 m 37 1 m 29 49 m 22 49 m

Admin .left side must be equal to right side = moment on the left side must be equal to moment on the right side. 520kg x 8m = 48kg x 7m + 170 kg x x .x is the distance between the pivot to mass c.x = 520kg x 8m 48kg x 7m / 170.x = 4160 336 / 170 = 22 49 m .distance between a and c is 8 m + 22 49 m = 30 49 m exemple 186 30,49 m.30,49 m.

Given .length of the mac 114 inches.forward gc limit 12% mac.aft cg limit 38% ?

Question 86-2 : 2 28 inches 8 77 inches 25 08 inches 10 53 inches

Consider a conventional aircraft with three wheels the nose jack is located 161 ?

Question 86-3 : Bem 42054 lb cg 680 3 in bem 24271 lb cg 610 9 in bem 42054 lb cg 570 3 in bem 24271 lb cg 936 in

exemple 194 Bem 42054 lb, cg 680.3 in.Bem 42054 lb, cg 680.3 in.

Refer to figure 031 61 .originally there has been 225 l of fuel in the tank of ?

Question 86-4 : The cg will move towards the nose of the aircraft the cg will move towards the tail of the aircraft the cg will move towards the bottom of the aircraft the cg will remain the same

exemple 198 The cg will move towards the nose of the aircraft.The cg will move towards the nose of the aircraft.

Refer to figure 031 05 .given .force fa 100 n.distance a 6 m.distance b 3 ?

Question 86-5 : 200 n 300 n 50 n 100 n

exemple 202 200 n.200 n.

Refer to figure 031 34 .given.bem 1200 kg.bem cg 3 00.pilot and front pax ?

Question 86-6 : 2 96 m 2 99 m 3 03 m 3 00 m

exemple 206 2.96 m.2.96 m.

Refer to figure 031 04 .given .force fa 100 n.distance a 6 m.distance b 3 ?

Question 86-7 : 50 n 200 n 300 n 50 n

exemple 210 50 n.50 n.

Select the correct statement for the cg safe range ?

Question 86-8 : The safe range falls between the front and rear cg limits and includes both limits the safe range falls between the front and rear cg limits but does not include them the safe range falls between the front and rear cg limits but only includes the aft limit the safe range falls between the front and rear cg limits but only includes the forward limit

exemple 214 The safe range falls between the front and rear cg limits and includes both limits.The safe range falls between the front and rear cg limits and includes both limits.

The fuel index is ?

Question 86-9 : Used to calculate the correct position of the cg due to different locations of the fuel tanks the difference between the zero fuel mass index and the doi a standard value given by easa and can be used for different types of aircraft only used for aeroplanes with wing tip tanks

exemple 218 Used to calculate the correct position of the cg due to different locations of the fuel tanks.Used to calculate the correct position of the cg due to different locations of the fuel tanks.

Refer to figure 031 03 .given .force fa 300 n.force fb 150 n.distance a 3 ?

Question 86-10 : 6 m 2 m 1 5 m 9 m

exemple 222 6 m.6 m.

Refer to figure 031 60 .given .weight 110800 kg.mac 31 6%.from the given values ?

Question 86-11 : 120 4 122 0 122 2 120 7

Note de moi this question also exists at examination with .weight 112600 kg mac 30 7% and an additional pilot of 75 kg in zone g answer is 119 3 exemple 226 120.4.120.4.

Refer to figure 031 55 .find the cg position as %mac for the take off ?

Question 86-12 : 24% 10 8% 20% 27%

exemple 230 24%.24%.

A mass of 600 kg is loaded at a station which is located 12 metres behind the ?

Question 86-13 : 108000 n m 10800 n m 72000 n m 115200 n m

exemple 234 108000 n.m108000 n.m

Refer to figure 031 00 .if the aft galley is loaded with 102 kg dry operating ?

Question 86-14 : 1 52592 0 01496 1 35048 there is no change in doi

exemple 238 1.52592.1.52592.

Refer to figure 031 02 .given .distance a 2 m.force fa 300 n.calculate force fc ?

Question 86-15 : 100 n 900 n 600 n 300 n

For this question use annex ecqb 031 048 v2015 07 calculate the centre of ?

Question 86-16 : 85 79 mm 87 59 mm 86 41 kg 85 79 kg mm

exemple 246 85.79 mm85.79 mm

A 5 m long plank is on a pivot located at 3 m of the left side a user applies a ?

Question 86-17 : 900 n 1500 n 600 n 1800 n

Ecqb04 dec 2018 . .3m x 600 n = 2m x n.1800 nm = 2m x n.1800 / 2 = 900 n exemple 250 900 n.900 n.

Refer to figure 031 52 .what is the forward cg limit and what is the aft cg ?

Question 86-18 : 87 3 and 94 6 86 4 and 94 2 82 and 94 5 87 2 and 94 2

exemple 254 87.3 and 94.6.87.3 and 94.6.

Refer to figure 031 46 .how much fuel could be loaded at reference station 4 ?

Question 86-19 : 806 l 1171 l 487 l 324 l

Calculate the values from the tanks at station 4 575 .236 litre.324 litre.246 litre. .806 litre exemple 258 806 l.806 l.

Length of the mean aerodynamic chord 1 m.moment arm of the forward cargo 0 50 ?

Question 86-20 : 110 kg 183 kg 165 kg 104 kg

Change in mass / total mass = change in cg / total distance moved.change in cg = 0 15 m 25%mac to 40%mac of 1 metre .total distance moved = distance between front forward cargo and aft cargo = 0 5 m to 2 5 m = 3 m.change in mass = total mass x change in cg / total distance moved.change in mass = 2200 x 0 15 /3 = 110 kg exemple 262 110 kg.110 kg.

For the transport aeroplane the moment balance arm for the forward hold ?

Question 86-21 : 367 9 inches 257 inches 314 5 inches 421 5 inches

Img149 exemple 266 367.9 inches.367.9 inches.

Referring to the loading manual for the transport aeroplane the maximum load ?

Question 86-22 : 68 kg per square foot 150 kg per square foot 68 lbs per square metre 68 kg per square meter

Img150 exemple 270 68 kg per square foot.68 kg per square foot.

The maximum intensity floor loading for an aeroplane is given in the flight ?

Question 86-23 : 416 kg 1015 6 kg 41 6 kg 101 6 kg

The max floor loading is 650 kg per square metre .the area of the pallet is 0 8m x 0 8m = 0 64 m² .650 kg x 0 64 = 416 kg exemple 274 416 kg416 kg

A pallet having a freight platform which measures 200 cm x 250 cm has a total ?

Question 86-24 : 285 5 kg may be added 158 3 kg must be off loaded 28 5 kg must be off loaded 28 5 kg may be added

Surface contact area = 0 2 m x 2 m x 2 ground supports = 0 8m².maximum permitted distribution load intensity .1m² converted in feet = 3 28 x 3 28 = 10 76 ft².0 8 x 10 76 = 8 61 ft².reference states that we can load 68 kg per ft² thus .68 x 8 61 = 585 3 kg.585 3 300 kg of the current pallet mass 285 5 kg may be added exemple 278 285.5 kg may be added.285.5 kg may be added.

From the loading manual for the jet transport aeroplane the maximum floor ?

Question 86-25 : 68 kg per square foot 150 kg per square foot 3305 kg in forward compartment and 4187 kg in aft compartment 7288 kg in forward compartment and 9232 kg in aft compartment

On the line of the aft cargo compartment table we read 'maximum distribution load intensity kg per ft ² ' 68 exemple 282 68 kg per square foot.68 kg per square foot.

From the loading manual for the transport aeroplane the aft cargo compartment ?

Question 86-26 : 4187 kg 9232 kg 1568 kg 3062 kg

Img151 exemple 286 4187 kg.4187 kg.

From the loading manual for the transport aeroplane the maximum load that can ?

Question 86-27 : 835 5 inches is 3062 kg 421 5 inches is 2059 lbs 421 5 inches is 4541 kg 835 5 inches is 6752 kg

Img152 exemple 290 835.5 inches is 3062 kg.835.5 inches is 3062 kg.

An aeroplane whose specific data is shown in the annex has a planned take off ?

Question 86-28 : Front cargo 3 740 kg rear cargo 6 760 kg front cargo 9 260 kg rear cargo 1 240 kg front cargo 6 760 kg rear cargo 3 740 kg front cargo 4 550 kg rear cargo 5 950 kg

Mean aerodynamic cord lenght = 18 6 m 14 m = 4 6 m.centre of gravity modification = 30% to 33% = 3%.3% of mac lenght = 3% of 4 6 m = 0 138 m.mass change / total mass = change of cg / total distance moved.mass change = change of cg x total mass / total distance moved.mass change = 0 138 m x 200000 kg / 10 m.mass change = 2760 kg.we have to transfer 2760 kg from the front cargo to the rear cargo in order to move the cg aft .front cargo = 6500 kg 2760 kg = 3740 kg .rear cargo = 4000 kg + 2760 kg = 6760 kg exemple 294 Front cargo: 3 740 kg, rear cargo: 6 760 kgFront cargo: 3 740 kg, rear cargo: 6 760 kg

The floor limit of an aircraft cargo hold is 5 000 n/m2 .it is planned to load ?

Question 86-29 : 80 kg 800 kg 32 kg 320 kg

Weight in kg = 5000 n/m² / 10 = 500 kg .500 x 0 4 x 0 4 = 80 kg exemple 298 80 kg.80 kg.

The floor of the main cargo hold is limited to 4000 n/m2 .it is planned to load ?

Question 86-30 : 100 kg 1000 kg 500 kg 5000 kg

Footprint of one cubic container is 0 5 x 0 5 = 0 25 m² .4000 n/m² x 0 25 m² = 1000 n.10 n = 1 kg.maximum gross mass must not exceed 100 kg per container exemple 302 100 kg.100 kg.

Given . actual mass 116 500 lbs. original cg station 435 0. compartment a ?

Question 86-31 : 433 3 463 7 506 3 436 7

Note that this is the only answer that moves the center of gravity forward .change in mass / total mass = change in cg / total distance moved.change in mass = 390 lbs.change in cg = .total distance moved = distance between a and b = 792 5 285 5 = 507..change in mass = total mass x change in cg / total distance moved.390 = 116500 x 507 / change in cg.change in cg = 507 x 390 / 116 500 = 1 70.station number of the new cg 435 0 1 7 = 433 3 exemple 306 433.3433.3

Pallet ground base 1 44 m² .the pallet is carried on two ground supports each ?

Question 86-32 : 351 kg 508 kg 175 kg 1054 kg

Area in contact with surface = 2 x 1 2 x 0 2 = 0 48 m².732 x 0 48 = 351 kg exemple 310 351 kg.351 kg.

The maximum floor loading for a cargo compartment in an aircraft is given as ?

Question 86-33 : 40 cm by 200 cm 30 cm by 300 cm 30 cm by 200 cm 40 cm by 300 cm

The minimum size that can be used .600 / 0 4 x 2 = 750 kg/m² .or.600 kg = 80% of 750 kg.80% of 1 m² = 0 8 m².40 x 200 = 800 cm² 0 8 m² exemple 314 40 cm by 200 cm.40 cm by 200 cm.

Given the following data how much cargo must be moved from the forward hold to ?

Question 86-34 : 2760 kg 2904 kg 6000 kg 1467 kg

Mean aerodynamic cord lenght = 18 6 m 14 m = 4 6 m.centre of gravity modification = 30% to 33% = 3%.3% of mac lenght = 3% of 4 6 m = 0 138 m.mass change / total mass = change of cg / total distance moved.mass change = change of cg x total mass / total distance moved.mass change = 0 138 m x 200000 kg / 10 m.mass change = 2760 kg exemple 318 2760 kg.2760 kg.

What is the maximum running load in the aft section of the forward lower ?

Question 86-35 : 13 12 kg/in 13 15 kg/in 14 65 kg/in 7 18 kg/in

Img174 exemple 322 13.12 kg/in.13.12 kg/in.

Palletised cargo ?

Question 86-36 : Consists of different cargo box on pallets stored in the cargo holds can be loaded without specific loading equipment consists of passenger baggage on pallets stored in the cargo holds has fallen out of use due to the lack of protection

exemple 326 Consists of different cargo box on pallets stored in the cargo holds.Consists of different cargo box on pallets stored in the cargo holds.

Bulk cargo ?

Question 86-37 : Can be loaded without specific loading equipment consists of different cargo box on pallets stored in the cargo holds consists of passenger baggage on pallets stored in the cargo holds has fallen out of use due to the lack of protection

Bulk cargo loose unpackaged non containerized cargo such as cement grains ores exemple 330 Can be loaded without specific loading equipment.Can be loaded without specific loading equipment.

Containerised cargo ?

Question 86-38 : Consists of baggage and cargo loaded into standard size containers stored in the cargo holds consists of different cargo box on pallets stored in the cargo holds can be loaded without specific loading equipment has fallen out of use due to the lack of protection

Containerised cargo baggage and cargo can be loaded into standard size containers designed to fit and lock into the cargo compartment the containers have an individual maximum mass limit and an individual floor loading limit mass per unit aera exemple 334 Consists of baggage and cargo loaded into standard size containers stored in the cargo holds.Consists of baggage and cargo loaded into standard size containers stored in the cargo holds.

Bulk cargo ?

Question 86-39 : Consists of cargo box baggage loosely loaded in the cargo holds consists of different cargo box on pallets stored in the cargo holds consists of passenger baggage on pallets stored in the cargo holds has fallen out of use due to the lack of protection

Bulk cargo can be loaded without specific loading equipment exemple 338 Consists of cargo (box, baggage) loosely loaded in the cargo holds.Consists of cargo (box, baggage) loosely loaded in the cargo holds.

Define the maximum load distribution ?

Question 86-40 : Load divided by smallest area mass per unit area load divided by largest area maximum admissible g force load

exemple 342 Load divided by smallest area.Load divided by smallest area.

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