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Question 123-1 : In the atc flight plan item 19, if the number of passengers to be carried is not known when the plan is ready for filing ? [ Preparation civilian ]

Tbn to be notified may be entered in the relevant box.

.icao doc4444 pans atm. /com en/com033 368.png.. exemple 223 Tbn (to be notified) may be entered in the relevant box.

Question 123-2 : An aircraft has a maximum certificated take off mass of 137000 kg but is operating at take off mass 135000 kg. in item 9 of the atc flight plan its wake turbulence category is ?

Heavy h.

Icao doc4444 pans atm. /com en/com033 537.png.. exemple 227 Heavy “h”.

Question 123-3 : In the appropriate box of an atc flight plan form, corresponding to the estimated time of departure, the time indicated is that at which the aircraft intends to ?

Go off blocks

exemple 231 Go off blocks

Question 123-4 : The planned departure time from the parking area is 1815 utc.the estimated take off time is 1825 utc.the flight plan must be filed with atc at the latest at ?

1715 utc

Mastadans.if the aerodrome is hj, flight plan may be submitted 30 minutes before eobt....no, the exam is icao, we are talking about icao flight plan ats flight plan...icao annex 2, rules of the air.3.3 flight plans.3.3.1 submission of a flight plan.....3.3.1.4 unless otherwise prescribed by the appropriate ats authority, a flight plan for a flight to be provided with air traffic control service or air traffic advisory service shall be submitted at least sixty minutes before departure , or, if submittedduring flight, at a time which will ensure its receipt by the appropriate air traffic services unit at least ten minutes before the aircraft is estimated to reach.a the intended point of entry into a control area or advisoryarea or.b the point of crossing an airway or advisory route. exemple 235 1715 utc

Question 123-5 : In the ats flight plan item 15, for a flight along a designated route, where the departure aerodrome is not on or connected to that route . 1522 ?

The letters 'dct' should be entered, followed by the point of joining the ats route.

Item 15.flights along designated ats routes.insert, if the departure aerodrome is located on or connected to the ats route, the designator of the first ats route,.or.if the departure aerodrome is not on or connected to the ats route, the letters dct followed by the point of joining the first ats route, followed by the designator of the ats route... dct means direct. exemple 239 The letters 'dct' should be entered, followed by the point of joining the ats route.

Question 123-6 : An aircraft plans to depart london at 1000 utc and arrive at munich eddm at 1215 utc. in the atc flight plan item 16 destination/eet should be entered with ?

Eddm0215

.extract from icao doc4444 pans atm. /com en/com033 406.png.eet estimated elapsed time.

Question 123-7 : On an atc flight plan you are required to indicate in the box marked 'speed' the planned speed for the first part of the cruise or for the entire cruise..this speed is ?

The true airspeed

exemple 247 The true airspeed

Question 123-8 : The wind direction and velocity °/kt at 50°n 040°e.. err a 033 417 ?

Is 020/70.

Img /com en/com033 1067.jpg. exemple 251 Is 020/70.

Question 123-9 : In the appropriate box of an atc flight plan, for endurance, one must indicate the time corresponding to ?

The total usable fuel on board.

Julien35.in question 294 for example, we have to remove from the useable fuel the reserve fuel to get the endurance..do you have a definition for endurance...'atc endurance' is different to 'safe endurance'. for 'atc endurance' we are considering the total usable fuel on board the longest time you can fly until your engines are going to stop..when calculating for the point of safe return psr , you must come back, or continue your flight, and land at departure or destination with your fuel reserve on board. exemple 255 The total usable fuel on board.

Question 123-10 : Item 9 of the ats flight plan includes 'number and type of aircraft'. in this case 'number' means .. err a 033 453 ?

The number of aircraft flying in a group.

.icao doc4444 pans atm. /com en/com033 537.png.. exemple 259 The number of aircraft flying in a group.

Question 123-11 : On a atc flight plan, to indicate that you will overfly the waypoint romeo at 120 kt at flight level 085, you will write ?

Romeo/n0120f085

exemple 263 Romeo/n0120f085

Question 123-12 : In the ats flight plan item 19, emergency and survival equipment carried on the flight should be indicated by . 1522 ?

Crossing out the box relevant to any equipment not carried.

Img1315 exemple 267 Crossing out the box relevant to any equipment not carried.

Question 123-13 : In the atc flight plan item 15, when entering a route for which standard departure sid and standard arrival star procedures exist ?

Both should be entered in the atc plan where appropriate.

.icao doc4444 pans atm. /com en/com033 476a.png.. example given in icao doc4444. /com en/com033 476b.png..departure from amsterdam schipol eham on sid lek2b, arriving at lisbon lppt on star fatim1a. exemple 271 Both should be entered in the atc plan where appropriate.

Question 123-14 : Which describes the maximum intensity of icing, if any, at fl180 in the vicinity of casablanca 33°n 008°w .. err a 033 481 ?

Severe.

Img629.. /com en/com033 481.jpg..even if symbol indicates moderate, icing is always to be considered as severe next to cb. exemple 275 Severe.

Question 123-15 : During an ifr flight tas and time appear to deviate from the data in the atc flight plan..the minimum deviations, that should be reported to atc in order to conform to pans rac, are ?

Tas 5% and time 3 minutes.

exemple 279 Tas 5% and time 3 minutes.

Question 123-16 : In the atc flight plan item 15 cruising speed , when not expressed as a mach number, cruising speed is expressed as ?

Tas.

.icao doc4444 pans atm. /com en/com033 490.png.. exemple 283 Tas.

Question 123-17 : In an atc flight plan, item 15 route , a cruising pressure altitude of 32000 feet would be entered as ?

F320

.icao doc4444 pans atm. /com en/com033 498.png.. exemple 287 F320

Question 123-18 : On an atc flight plan, to indicate that you will overfly the waypoint tango at 350 kt at flight level 280, you write ?

Tango/n0350f280

exemple 291 Tango/n0350f280

Question 123-19 : In the atc flight plan item 15, it is necessary to enter any point at which a change of cruising speed takes place. for this purpose a 'change of speed' is defined as ?

5% tas or 0.01 mach or more.

.icao doc4444 pans atm. /com en/com033 522.png.. exemple 295 5% tas or 0.01 mach or more.

Question 123-20 : Which of the following statements regarding filing a atc flight plan is correct ?

In case of atfm air traffic flow management the flight plan should be filed at least three hours in advance of the eobt.

Atfm air traffic flow management is defined as a function established with the objective of contributing to a safe, orderly and expeditious flow of air traffic by ensuring that atc capacity is utilised to the maximum extent possible, and that the traffic volume is compatible with the capacities declared by the appropriate air traffic service providers..in case of atfm air traffic flow management the flight plan should be filed at least three hours in advance of the eobt. exemple 299 In case of atfm (air traffic flow management) the flight plan should be filed at least three hours in advance of the eobt.

Question 123-21 : For the purposes of item 9 wake turbulence category of the atc flight plan, an aircraft with a maximum certificated take off mass of 62000 kg is ?

Medium 'm'.

.icao doc4444 pans atm. /com en/com033 537.png.. exemple 303 Medium 'm'.

Question 123-22 : The navigation plan reads.trip fuel 100 kg.flight time 1h35min.taxi fuel 3 kg.block fuel 181 kg.the endurance on the icao flight plan should read ?

2h 49min.

.fuel on board at take off is..181 kg 3 kg = 178 kg...fuel flow = trip fuel / flight time = 100 kg / 1h35min = 100/95 = 1.052 kg/min..endurance = 178 / 1.052 = 169 minutes 2h 49min. exemple 307 2h 49min.

Question 123-23 : You have a flight plan ifr from amsterdam to london. in the flight plan it is noted that you will deviate from the ats route passing the fir boundary amsterdam/london..the airway clearance reads cleared to london via flight planned route..which of the following statements is correct ?

The route according to the flight plan is accepted.

exemple 311 The route according to the flight plan is accepted.

Question 123-24 : In the atc flight plan item 13, in a flight plan submitted before departure, the departure time entered is the ?

Estimated off block time

exemple 315 Estimated off-block time

Question 123-25 : Given.planned and actual data as shown in the flight log excerpt..arriving overhead gamma you are cleared for direct routeing to mike. the flight time for direct flight gamma to mike will be 1 h 08 min, assuming other flight data remains constant, what fuel will be expected on arrival overhead ?

1272 kg.

Beta to gamma 25 minutes...fuel used 2760 2360 = 400 kg..fuel flow from beta to gamma 400 / 25 = 16 kg/min..fuel used from gamma to mike 68 mins x 16 kg = 1088 kg...on arrival overhead mike, fuel on board will be..2360 1088 = 1272 kg. exemple 319 1272 kg.

Question 123-26 : A turbojet aeroplane flies using the following data.flight level fl 330.flight regime 'long range' lr.mass 156 500 kg.tailwind component at this level 40 kt..with a remaining flight time of 1 h 10 min the ground distance that can be covered by the aeroplane at cruising speed is.. err a 033 2 ?

539 nm.

For a mass of 156500 kg, the table shows a tas of 427 kt right column..we have 40 kt tailwind component, our groundspeed is 467 kt...the ground distance that can be covered by the aeroplane at cruising speed is.467 x 70/60 = 545 nm close to 539 nm. exemple 323 539 nm.

Question 123-27 : Given.true course tc 017°.w/v 340°/30 kt.true air speed tas 420 kt.find.wind correction angle wca and ground speed gs ?

Wca 2°, gs 396 kt.

Wind correction angle wca is another term for drift, except drift is expressed as left or right, the wind correction angle uses '+' or ' '...under index, set true track 017°, centre dot on tas, 420 kt, with the rotative scale, set wind 340°/30 kt.. /com en/com033 38a.jpg..drift is always measured from heading to track, so turn to set true heading 015.5° 017° 2.5° right drift under index.. /com en/com033 38b.jpg.you now read a ground speed of 396 kt a drift of 2º right wca is 2º. exemple 327 Wca -2°, gs 396 kt.

Question 123-28 : The true course is 042°..the variation in the area is 6° w and the wind is calm..the deviation card is reproduced in the annex..in order to follow this course, the pilot must fly a compass heading of.. err a 033 41 ?

052°.

Use this very useful table for those questions. /com en/com033 41.jpg..the nearest compass deviation reading is taken from 045°, indicating 4° less than actual magnetic heading. add 4° onto the 048° magnetic heading giving the answer of 052° compass heading. exemple 331 052°.

Question 123-29 : At reference or see flight planning manual mrjt 1 figure 4.3.5..given a trip time of about 9 hours, within the limits of the data given, a temperature decrease of 30°c will affect the trip time by approximately.. err a 033 67 ?

By 7%.

. /com en/com033 67.jpg..a 9h trip becomes 8.6 for isa +20°c..a 9h trip becomes 9.2 for isa 10°c....difference for 30°c will affect the trip time by approximately.. 0.6/8.6 x 100 = 7%. exemple 335 By 7%.

Question 123-30 : At reference or see flight planning manual mrjt 1 figure 4.5.4..planning an ifr flight from paris to london for the twin jet aeroplane..given.estimated landing mass 49700 kg.fl 280.w/v 280°/40 kt.average true course 320°.procedure for descent.74 m/250 kias.determine the distance from the top of ?

76 nm.

.from the table.. /com en/com033 75.jpg..time 19 minutes.distance nam 86 nm..tas = distance/time = 86/19 x 60 = 272 kt...on nav computer.true course 320°.w/v 280°/40 kt.ground speed is 240 kt..distance nm from the top of descent to london = 240 x 19/60 = 76 nm. exemple 339 76 nm.

Question 123-31 : At reference or see flight planning manual mrjt 1 figure 4.7.3..given.diversion distance 720 nm.tail wind component 25kt.mass at point of diversion 55000kg.temperature isa.diversion fuel available 4250 kg.what is the minimum pressure altitude at which the above conditions may be met.. err a 033 76 ?

25000 ft.

. /com en/com033 76.jpg.. exemple 343 25000 ft.

Question 123-32 : Flight planning chart for an aircraft states, that the time to reach the cruising level at a given gross mass is 36 minutes and the distance travelled is 157 nm zero wind..what will be the distance travelled with an average tailwind component of 60 kt ?

193 nm.

.we know that a headwind or a tailwind component does not modify the time to climb to a specific level, thus, we only have to calculate our speed..157 x 60 / 36 = 262 kt...adding tail wind component..262 + 60 = 322 kt....the distance travelled in 36 minutes will be..322 x 36 / 60 = 193 nm. exemple 347 193 nm.

Question 123-33 : At reference or see flight planning manual mrjt 1 figure 4.3.6..given.distance to alternate 400 nm.landing mass at alternate 50 000kg.headwind component 25 kt.the alternate fuel required is.. err a 033 79 ?

2800 kg.

Answer... /com en/com033 1012.jpg exemple 351 2800 kg.

Question 123-34 : At reference or see flight planning manual mrjt 1 figure 4.3.6..given.twin jet aeroplane.dry operating mass 35500 kg.traffic load 14500 kg.final reserve fuel 1200 kg.distance to alternate 95 nm.tailwind component 10 kt.find.fuel required and trip time to alternate with simplified flight planning ?

1000 kg, 24 min.

Img /com en/com033 1015.jpg exemple 355 1000 kg, 24 min.

Question 123-35 : Given.planning data as shown in the flight log excerpt fuel planning section..after a balked landing at the destination airport, you have to divert to the alternate airport with the gear extended..the re calculated flight time to the alternate due to the reduced speed is 1 h 10 min and the fuel flow ?

5987 kg.

900 x 70/60 = 1050 kg to reach the alternate airport....subtract 1050 kg from our estimated landing mass at destination...7037 1050 = 5987 kg. exemple 359 5987 kg.

Question 123-36 : Flight planning chart for an aeroplane, states that the time to reach fl 190 at a given gross mass is 22 minutes and the distance travelled is 66 nm no wind..what will be the distance travelled with an average head wind component of 35 kt ?

53 nm.

.the time to reach fl 190 is 22 minutes and the distance travelled is 66 nm no wind..with a head wind component of 35 kt, our ground distance travelled will be less, but the time to reach fl 190 remains unchanged...we need first to know our ground speed without wind.66/22 x 60 = 180 kt...with 35 kt head wind, our ground speed becomes.180 35 = 145 kt...in 22 minutes, the distance travelled will be 145/60 x 22 = 53.17 nm. exemple 363 53 nm.

Question 123-37 : At reference or see flight planning manual mrjt 1 figure 4.5.3.1.given twin jet aeroplane.fl 330.long range cruise.outside air temperature 63°c.gross mass 50500 kg.true air speed tas is.. err a 033 126 ?

420 kt.

. /com en/com033 126.jpg..isa temperature at fl330 is 15°c 2°c x 33 = 51°c...adjustements for operation at non standard temperatures, decrease tas by 1 knot per degree c below isa. difference between 63°c and 51°c is 12°c.433 12 = 421 kt... ninorr.this make no difference to the answer but on the picture you have marked wrong mass should be 50500 not 55000 as you marked. exemple 367 420 kt.

Question 123-38 : At reference or see flight planning manual mrjt 1 figure 4.5.3.1. given long range cruise.oat 45°c at fl 350.gross mass at the beginning of the leg 40000 kg.gross mass at the end of the leg 39000 kg..find true air speed tas and cruise distance nam for a twin jet aeroplane.. err a 033 147 ?

Tas 432 kt, 227 nam.

.isa at fl350 is 35 x 2° + 15° = 55°c..gross mass at the end of the leg 39000 kg, from the table, we can read a tas of 422 kt, as we are at isa+9, we must increase tas by 1 kt per degree c above isa as indicated on the bottom of the table .422 + 10 = 432 kt.....fuel consumption on the leg was 1000 kg 40000 39000 , table values are..40000 >1163 nam..39000 > 936 nam....1163 936 = 227 nam. exemple 371 Tas 432 kt, 227 nam.

Question 123-39 : During an ifr flight in a beech bonanza the fuel indicators show that the remaining amount of fuel is 100 lbs after 38 minutes..fuel at take off is 160lbs..for the alternate fuel, 30 lbs is necessary..the planned fuel for taxi is 13 lbs..final reserve fuel is estimated at 50 lbs..if the fuel flow ?

12 minutes.

Minimum take off fuel = trip fuel + contingency + alternate + final reserve..after 38 min, 60 lbs of fuel has been used.fuel flow = 60/38 = 1.579 lb/min...at landing at destination, alternate fuel and final reserve must be in your tank..100 lbs 30 + 50 = 20 lbs....we can fly 20/1.579 = 12.66 min. exemple 375 12 minutes.

Question 123-40 : Given.planning data as shown in the flight log excerpt fuel planning section..after a balked landing at the destination airport, you have to divert to the alternate airport with the gear extended..the re calculated flight time to the alternate due to the reduced speed is 2h 20 min and the fuel flow ?

5440 kg.

Dadoki .2,333 2h 20min x 780 = 1820..1820 1100 alternate fuel 990 reserve = 270..4370 dom + 500 traffic load + 90 contingency + 210 final reserve + 270 remaining of alternate and extra fuel = 5440 kg. exemple 379 5440 kg.


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