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Question 179-1 : Which of the aeronautical chart symbols indicates a basic non specified navigation aid . 2513 ? [ Practice protocol ]
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Admin . 2512
Question 179-2 : Which of the aeronautical chart symbols indicates a tacan . 2513 ?
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Question 179-3 : Which of the aeronautical chart symbols indicates a vortac . 2513 ?
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Question 179-4 : Which aeronautical chart symbol indicates a flight information region fir boundary . 2509 ?
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Admin . 2510
Question 179-5 : Which aeronautical chart symbol indicates a control zone boundary . 2509 ?
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Question 179-6 : Which aeronautical chart symbol indicates an uncontrolled route . 2509 ?
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Question 179-7 : Which aeronautical chart symbol indicates the boundary of advisory airspace . 2509 ?
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Question 179-8 : Which aeronautical chart symbol indicates a non compulsory reporting point . 2509 ?
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Question 179-9 : Which aeronautical chart symbol indicates a compulsory reporting point . 2509 ?
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Admin . 2510
Question 179-10 : Which aeronautical chart symbol indicates a waypoint . 2509 ?
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Admin . 2510
Question 179-11 : Which aeronautical chart symbol indicates an unlighted obstacle . 2509 ?
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Question 179-12 : Which aeronautical chart symbol indicates a lighted obstacle . 2509 ?
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Question 179-13 : Which aeronautical chart symbol indicates a group of unlighted obstacles . 2509 ?
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Question 179-14 : Which aeronautical chart symbol indicates a group of lighted obstacles . 2509 ?
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Question 179-15 : Which aeronautical chart symbol indicates an exceptionally high unlighted obstacle . 2509 ?
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Question 179-16 : Which aeronautical chart symbol indicates an exceptionally high lighted obstacle . 2509 ?
14
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Question 179-17 : What is the meaning of aeronautical chart symbol n°15 . 2509 ?
Aeronautical ground light
Admin . 2512
Question 179-18 : What is the meaning of aeronautical chart symbol no 16 . 2509 ?
Lightship
Admin . 2512
Question 179-19 : Which aeronautical chart symbol indicates an aeronautical ground light . 2509 ?
15
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Question 179-20 : Which aeronautical chart symbol indicates a lightship . 2509 ?
16
Admin . 2512
Question 179-21 : Given .a polar stereographic chart of the northern hemisphere whose grid is aligned with the zero meridian .grid track 344° longitude 115°00'w calculate the true course ?
229°
Admin .let's assume the airplane is at latitude 70°n . 2059.true course = 344° 115° = 229° . ninorr .just remember simple quote . grid track = true track + west longitude or east longitude .so in this case 344 = x + 115.x = 344 115.x = 229
Question 179-22 : A straight line is drawn on a lamberts conformal conic chart between two positions of different longitude .the angular difference between the initial true track and the final true track of the line is equal to ?
Chart convergency
Admin .chart convergency means the rate at which meridians drawn on a chart are converging . 2060.if you drawn a line between two positions of different longitude the angular difference between the initial true track and the final true track is equal to chart convergency
Question 179-23 : If the chart scale is 1 500 000 what earth distance would be represented by 7 cm on the chart ?
35 000 m
.7 cm x 500 000 cm = 3 500 000 cm = 35 000 m or 35 km
Question 179-24 : What is the constant of the cone for a lambert conic projection whose standard parallels are at 50°n and 70°n ?
0 866
Constant of cone convergency factor the ratio between the top angle of the unfolded cone and 360° or sine of the parallel of origin .the parallel of origin is about half way between the standard parallels .midway between 50°n and 70°n is 60°n .sin of 60° = 0 866
Question 179-25 : On a direct mercator projection a particular chart length is measured at 30°n what earth distance will the same chart length be if measured at 60°n ?
A smaller distance
Admin . 1753. direct mercator chart .earth distance along a parallel of latitude is known as 'departure' .earth distance between two meridians along a parallel of latitude departure = difference of longitude x 60 nm x cos latitude .cos 30 = 0 866.cos 60 = 0 5.if for example the length on the chart is 5° of longitude and measures 10 cm long the distance on earth at 30°n is .distance = 5° x 60 nm x 0 866 = 260 nm .at 60°n and since the direct mercator chart is of rectangular shape 10 cm = 5° of longitude also .distance = 5° x 60 nm x 0 5 = 150 nm
Question 179-26 : How does the scale vary in a direct mercator chart the scale ?
Increases with increasing distance from the equator
Admin . 1753.on earth 1° of longitude = 60 nm at the equator.at 45°n or s 1° of longitude = 60 nm x cos45° = 42 5 nm.if you look at a direct mercator chart the scale between each degrees of longitude remains unchanged even if you are at 30°n 45°n or 60°n the scale increases with the secant of latitude
Question 179-27 : How does the chart convergency change with latitude in a lambert conformal projection ?
It is constant and does not change with latitude
Admin . 2052.meridians are converging at a constant rate regardless of latitude
Question 179-28 : How does the convergency of any two meridians on the earth change with varying latitude ?
It changes as sine of latitude
Question 179-29 : Grid heading is 299° grid convergency is 55° west and magnetic variation is 90° west what is the corresponding magnetic heading ?
084°
.'convergence east true track least' or 'convergence west true track best' .grid convergency is 55° west .299° + 55° = 354° true track .'variation east magnetic least' or 'variation west magnetic best' .magnetic variation is 90° west .354° + 90° 084° magnetic heading
Question 179-30 : Where on a direct mercator projection is the chart convergency correct compared to the earth convergency ?
At the equator
Admin .a cylindrical projection based on the equator is a direct mercator projection . 2044.chart convergency = earth convergency at the equator .convergency is the angle of inclination between two selected meridians measured at a given latitude and is equal to the difference between the great circle directions measured at each meridian
Question 179-31 : A route a to b is drawn on a polar stereographic chart with the grid aligned with the greenwich meridian the true track of the straight line at a is 060° when passing the meridian 100°e the true track is 090° .the grid track of this route on the chart is ?
350° g
.the easiest way to solve this exercice is to draw the situation . 2033
Question 179-32 : The standard parallels of a lambert chart are 26°n and 48°n and the stated scale is 1 2 500 000 .which statement is correct ?
The scale at 28°n is smaller than the scale at 24°n
.at 26°n and 48°n the stated scale is correct 1 cm = 2 500 000 cm .on a lambert chart the scale contracts between the standard parallels and expands outside so the scale at 28°n is smaller than the scale at 24°n
Question 179-33 : Which statement is correct about the scale of a polar stereographic projection of the northern polar area ?
The scale reaches its minimum value at the north pole
Admin .on a polar stereographic chart meridians are straight lines originating from the pole parallels of latitude are arcs of circles centred at the pole .the scale is correct at the pole elsewhere it expands as sec² 1/2 co latitude within 1% from latitudes 90° to 78° within 3% from latitudes 78° to 70°
Question 179-34 : Which statement is correct about the scale of a lambert projection ?
The scale reaches its minimum value at the parallel of origin
Admin .the lambert conformal projection is what most of today's aeronautical charts are based on . 1776.on a lamberts chart scale is correct at the standard parallels as this is where the paper touches the reduced earth and since the surface of the reduced earth is bulging out from the paper between the standard parallels it will have to be squashed in order to fit onto the paper this will then lead to a smaller scale for the area between the standard parallels
Question 179-35 : A route is flown from 80°s 100°w to 80°s 140°e at 180°e/w the grid track gt and true track tt on a polar stereographic chart whose grid is aligned with the greenwich meridian are respectively ?
110° g and 290° t
.draw the situation . /com en/com061 598 jpg.those questions are not looking your calculation skill but your facility to visualize a situation
Question 179-36 : A route is flown from 85°s 100°e to 85°s 140°w at 180°e/w the grid track gt and true track tt on a polar stereographic chart whose grid is aligned with the greenwich meridian are respectively ?
250° g and 070° t
.draw the situation . /com en/com061 599 jpg.those questions are not looking your calculation skill but your facility to visualize a situation
Question 179-37 : The positions a 30°00'n 017°30'e and b at longitude 30°00'n 023°30'e are plotted on a lambert chart with a constant of the cone of 0 5 .a and b are connected by a straight line .the true track measured at a is 088 5° .what is the true track measured at b ?
091 5°
.draw the situtation . /com en/com061 601 jpg.if we were on a mercator chart we would have a curve blue line for the great circle track and a straight line for the rhumb line in northern hemisphere our arrival track at b will be more than our departure track at a .simply calculate convergency = 6° x 0 5 = 3°.true track at b = 88 5° + 3° = 91 5°
Question 179-38 : A route is flown from 85°s 100°e to 85°s 140°w at 160°e the grid track gt and true track tt on a polar stereographic chart with a grid orientated on the 180° meridian are respectively ?
070° g and 090° t
. /com en/com061 604 jpg.
Question 179-39 : A straight line from a 75°s 120°e to b 75°s 160°e is drawn on a polar stereographic chart when passing the meridian 155°e the true track is ?
075°
. /com en/com061 607a jpg. /com en/com061 607b jpg.drawn the situation the answer becomes simple and clear
Question 179-40 : On a mercator's projection the distance between 17°n 035°e and 17°n 040°e is 5 cm .the scale at 57°n is approximately ?
1 6 052 030
.on a mercator chart meridians of longitude are parallel lines .5 cm distance at 17°n = 5 cm at 57°n..distance on earth between the two points .distance on earth = change of longitude x cos latitude.distance on earth = 5°x 60' x cos57°.distance on earth = 164 nm ..so we can say that 5 cm on the chart = 164 nm on earth..164 nm x 1 852 = 303 728 km.303 728 km x 1000 = 303 728 m.303 728 m x 100 = 30 72 800 cm..30 72 800 cm / 5 cm = 6 074 560.the scale at 57°n is approximately 1 6 074 560
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