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Question 97-1 : Can the length of a stopway be added to the runway length to determine the take off distance available ? [ Attainment AIM ]

No

Question 97-2 : May anti skid be considered to determine the take off and landing data ?

Yes.

Rejected take off and landing performance are determined by a multitude of variables airplane weight and configuration use of deceleration devices airport elevation atmospheric temperature wind runway length runway slope and runway surface condition ie dry wet contaminated improved unimproved grass etc are all factors in determining stopping performance inoperative anti skid braking will have a direct impact on the airplane's distance calculation to come to a full stop
exemple 201: Yes
No. only for take-off. only for landing.

Question 97-3 : In case of an engine failure recognized below v1 ?

The take off must be rejected.

exemple 205: The take off must be rejected
The take-off may be continued if a clearway is available. the take-off should only be rejected if a stopway is available. the take-off is to be continued unless v1 is less than the balanced v1.

Question 97-4 : In case of an engine failure which is recognized at or above v1 ?

The take off must be continued.

exemple 209: The take off must be continued
The take-off must be rejected if the speed is still below vlof. a height of 50 ft must be reached within the take-off distance. the take-off should be rejected if the speed is still below vr.

Question 97-5 : The take off distance available is ?

The length of the take off run available plus the length of the clearway available.

The take off distance available is the length of the take off run available plus the length of the clearway available in the following limit take off the take off distance must not exceed the take off distance available with a clearway distance not exceeding half of the takeoff run available
exemple 213: The length of the take off run available plus the length of the clearway available
The runway length minus stopway. the runway length plus half of the clearway. the total runway length, without clearway even if this one exists.

Question 97-6 : The result of a higher flap setting up to the optimum at take off is ?

A shorter ground roll.

The result of a higher flap setting up to the optimum at take off is a shorter ground roll but the advantage of early lift off can be lost in this first part of the climb you may not be able to clear the obstacle with that higher flap settingthe use of flaps is especially beneficial for a short runway with no obstacles or only a low obstacle further away not using flaps is beneficial for a very long runway with a nearby obstaclethe picture below shows the choices in a somewhat exaggerated way 1074
exemple 217: A shorter ground roll
An increased acceleration. a higher v1. a longer take-off run.

Question 97-7 : How is wind considered in the take off performance data of the aeroplane operations manuals ?

Not more than 50% of a headwind and not less than 150% of the tailwind.

exemple 221: Not more than 50% of a headwind and not less than 150% of the tailwind
Unfactored headwind and tailwind components are used. not more than 80% headwind and not less than 125% tailwind. since take-offs with tailwind are not permitted, only headwinds are considered.

Question 97-8 : A higher pressure altitude at isa temperature ?

Decreases the field length limited take off mass.

Pressure altitude is the height in the standard atmosphere that you may find a given pressure if you set 1013 hpa on the subscale and your altimeter reads 2000 ft the pressure altitude is 2000 ftthus higher pressure altitude is similar to a higher field elevationair density reduces with atmoshperic pressure less density less lifttake off distance increases and the take off mass limited by the field length must be decreased
exemple 225: Decreases the field length limited take off mass
Decreases the take-off distance. increases the climb limited take-off mass. has no influence on the allowed take-off mass.

Question 97-9 : A higher outside air temperature oat ?

Decreases the brake energy limited take off mass.

Maximum brake energy speed vmbe is the speed from which the aeroplane may be brought to a stop without exceeding the maximum energy absorption capability of the brakesvi must not exceed the vmbe otherwise the aircraft cannot be stopped within the asda in case of engine failure during take off when vi exceeds the vmbe take off weight must be reduced so that vi is within the vmbe limit this reduced weight is the vmbe limit weightvmbe is based upon the kinetic energy of the aircraft and kinetic energy of an aircraft of mass m traveling at a speed v is 12 mv²air density will be less for a higher outside air temperature therefore you need a higher speed to get the lift for taking offthere is a risk of exceeding the capability of the brakes to stop the aircraft
exemple 229: Decreases the brake energy limited take off mass
Increases the field length limited take-off mass. increases the climb limited take-off mass. decreases the take-off distance.

Question 97-10 : The take off distance required increases ?

Due to slush on the runway.

The runway surface condition has effect on the wheel drag if the runway is contaminated by snow slush or standing water the wheel drag will be greater thus the accelerating force decreases and the take off distance required increases 1813 1812
exemple 233: Due to slush on the runway
Due to downhill slope because of the smaller angle of attack. due to head wind because of the drag augmentation. due to lower gross mass at take-off.

Question 97-11 : Due to standing water on the runway the field length limited take off mass will be ?

Lower.

Take off and landing distances are affected by standing water on the runway on take off friction increase as if we were on a grass runway that lead to increase take off run field length limited take off mass will be loweron landing we can imagine that the friction will help to stop the aircraft but in fact not standing water can lead to hydroplaning and grass will also reduce our brake capability
exemple 237: Lower
Higher. unaffected. only higher for three and four engine aeroplanes.

Question 97-12 : On a dry runway the accelerate stop distance is increased ?

By uphill slope.

The uphill slope = acceleration is slowerthe uphill slope = breaking is betterthe remaining distance for breaking is less so the accelerate stop distance is increased
By headwind. by low outside air temperature. by a lower take-off mass because the aeroplane accelerates faster to v1.

Question 97-13 : Uphill slope ?

Increases the take off distance more than the accelerate stop distance.

Takeoff distance is we must be at 35 ft at the end of toda with an engine outaccelerated stop distance is the distance required to accelerate to v1 with all engines at takeoff power experience an engine failure at v1 and abort the takeoff and bring the airplane to a stop using only braking action without the use of reverse thrustwith a uphill slope our acceleration will be slower our take off run is increased thus our take off distance is increasedin case of malfunction at v1 if we stop we will benefit from the uphill slope our braking distance is reduced slower acceleration but better braking
exemple 245: Increases the take off distance more than the accelerate stop distance
Decreases the accelerate stop distance only. decreases the take-off distance only. increases the allowed take-off mass.

Question 97-14 : V2 has to be equal to or higher than ?

11 vmca.

V2 can be limited by 11 vmca or by 113 vsr or 108 vsr for turbo propeller powered aeroplanes with more than three engines at low field elevation there will be a high vmca because of the high asymetric thrustv2 min based on vmca is 11 vmcaat low take off mass and with a large flap selection the 113 vsr or 108vsr will be less restrictive than the 11 vmcathis is from cs 25 certification specifications v2min in terms of calibrated airspeed may not be less than 1 113 vsr for i two engined and threeengined turbo propeller powered aeroplanes and ii turbojet powered aeroplanes without provisions for obtaining a significant reduction in the one engine inoperative power on stall speed 2 108 vsr for i turbo propeller powered aeroplanes with more than three engines and ii turbojet powered aeroplanes with provisions for obtaining a significant reduction in the one engine inoperative power on stall speed and 3 110 times vmc established under cs 25149vsr reference stall speed
1.15 vmcg. 1.1 vso. 1.15 vr.

Question 97-15 : V1 has to be ?

Equal to or higher than vmcg.

exemple 253: Equal to or higher than vmcg
Equal to or higher than vmca. higher than vr. equal to or higher than v2.

Question 97-16 : Under which condition should you fly considerably lower 4 000 ft or more than the optimum altitude ?

If at the lower altitude either considerably less headwind or considerably more tailwind can be expected.

exemple 257: If at the lower altitude either considerably less headwind or considerably more tailwind can be expected
If the maximum altitude is below the optimum altitude. if at the lower altitude there is a greater headwind. if at the lower altitude there is less tailwind.

Question 97-17 : Which statement is correct for a descent without engine thrust at maximum lift to drag ratio speed ?

The higher the gross mass the greater is the speed for descent.

exemple 261: The higher the gross mass the greater is the speed for descent
The higher the gross mass the lower is the speed for descent. the higher the average temperature (oat) the lower is the speed for descent. the mass of an aeroplane does not have any effect on the speed for descent.

Question 97-18 : The maximum mass for landing could be limited by ?

The climb requirements with one engine inoperative in the approach configuration.

You must always be prepared to go around this is the reason why in case of a landing with one engine inoperative the climb requirements must be met and keep in mind that you might remain stuck in the approach configuration if climb requirements cannot be met adjust the landing weight accordingly to meet climb requirements
exemple 265: The climb requirements with one engine inoperative in the approach configuration
The climb requirements with one engine inoperative in the landing configuration. the climb requirements with all engines in the approach configuration. the climb requirements with all engines in the landing configuration but with gear up.

Question 97-19 : On a long distance flight the gross mass decreases continuously as a consequence of the fuel consumptionthe result is ?

The specific range and the optimum altitude increases.

The optimum altitude increases all the time as the mass decreasesthe fuel flow decreases as the mass decreasesspecific air range = tas fuel flowas altitude increases tas increases therefore specific air range increases
exemple 269: The specific range and the optimum altitude increases
The speed must be increased to compensate the lower mass. the specific range increases and the optimum altitude decreases. the specific range decreases and the optimum altitude increases.

Question 97-20 : With one or two engines inoperative the best specific range at high altitudes is assume altitude remains constant ?

Reduced.

With one or two engines inoperative at high altitudes thrust is reduced speed will reduce you will have more drag you need to increase the angle of attack to increase the lift coefficient in order to maintain altitude you will generate more and more drag and you must apply max thrust on the remaining engine s the best specific range is reduced
exemple 273: Reduced
Improved. not affected. first improved and later reduced.

Question 97-21 : In unaccelerated climb ?

Thrust equals drag plus the downhill component of the gross weight in the flight path direction.

1089in unaccelerated climb thrust equals drag plus the downhill component of the gross weight in the flight path direction
exemple 277: Thrust equals drag plus the downhill component of the gross weight in the flight path direction
Lift is greater than the gross weight. lift equals weight plus the vertical component of the drag. thrust equals drag plus the uphill component of the gross weight in the flight path direction.

Question 97-22 : The rate of climb is approximately equal to ?

The still air gradient multiplied by the tas.

Example 1 kt = 10111667 ftmintas 100ktslope still air gradient 35%rate of climb = 100 x 35 100 = 35 kt 35 kt = 3539 ftmin the question states approximately
exemple 281: The still air gradient multiplied by the tas
The still-air gradient divided by the tas. the angle of climb multiplied by the tas. the angle of climb divided by the tas.

Question 97-23 : If the thrust available exceeds the thrust required for level flight ?

The aeroplane accelerates if the altitude is maintained.

If thrust is greater than drag the speed will increase if less the plane will slow down if lift is greater than weight the plane will climb if less the plane will descendin order to maintain altitude you must decrease the angle of attack the lift remains unchanged thus the aeroplane will accelerate since only v² in the lift formula cl x 12 rho v² x s can changed lift formula cl x 12 rho v² x scl = lift coefficientrho = densityv = tas in ms s = surface
exemple 285: The aeroplane accelerates if the altitude is maintained
The aeroplane descends if the airspeed is maintained. the aeroplane decelerates if it is in the region of reversed command. the aeroplane decelerates if the altitude is maintained.

Question 97-24 : Any acceleration in climb with a constant power setting ?

Decreases the rate of climb and the angle of climb.

With a constant power setting you must reduce your angle of climb to accelerate your rate of climb will also be reduced
exemple 289: Decreases the rate of climb and the angle of climb
Improves the climb gradient if the airspeed is below vx. improves the rate of climb if the airspeed is below vy. decreases rate of climb and increases angle of climb.

Question 97-25 : As long as an aeroplane is in a steady climb ?

Vx is always less than vy.

best angle of climb vx is performed at an airspeed that will produce the most altitude gain in a given distance vx is considerably lower than best rate of climb vy and is the airspeed where the most thrust is available over that required for level flight vy will result in a steeper climb path although the airplane will take longer to reach the same altitude than it would at vyvx is used in clearing obstacles after takeoff best rate of climb vy is performed at an airspeed where the most excess power is available over that required for level flight this condition of climb will produce the most gain in altitude in the least amount of time maximum rate of climb in feet per minute vy made at full allowable power is a maximum climb it must be fully understood that attempts to obtain more climb performance than the airplane is capable of by increasing pitch attitude will result in a decrease in the rate of altitude gainit should be noted that as altitude increases the speed for vx increases and the speed for vy decreases the point at which these two speeds meet is the absolute ceiling of the airplane
exemple 293: Vx is always less than vy
Vx may be greater or less than vy depending on altitude. vx is always greater than vy. vy is always greater than vmo.

Question 97-26 : The best rate of climb at a constant gross mass ?

Decreases with increasing altitude since the thrust available decreases due to the lower air density.

The higher you go the less power you will haveyou can increase the angle of climb and best rate of climb only if you have an excess of thrust or a rate of climb excess power
exemple 297: Decreases with increasing altitude since the thrust available decreases due to the lower air density
Increases with increasing altitude since the drag decreases due to the lower air density. increases with increasing altitude due to the higher true airspeed. is independent of altitude.

Question 97-27 : The climb gradient is defined as the ratio of ?

The increase of altitude to horizontal air distance expressed as a percentage.

The climb gradient is defined as the ratio expressed as a percentage of the change in geometric height divided by the horizontal distance traveledgradient = change in heighthorizontal distance x 100%for small angles of climb you can use rate of climb true airspeed but this is not the exact definition of the climb gradient
exemple 301: The increase of altitude to horizontal air distance expressed as a percentage
The increase of altitude to distance over ground expressed as a percentage. true airspeed to rate of climb. rate of climb to true airspeed.

Question 97-28 : Higher gross mass at the same altitude decreases the gradient and the rate of climb whereas ?

Vy and vx are increased.

Vx is the speed where you will have max excess thrust and vy is the speed where you will have max excess of poweras mass increases induced drag increases and the total drag curve moves up and right 1090trhust required curve showing total drag and power required curve showing required power 1135on the power curve for the propeller driven aircraft curve the lowest point of the curve vmp is the tas at wich the least power is needed as opposed to producing the least drag and is therefore the maximum rate of climb speed vy because the gap between power required and power available is greatest more power is needed above and below the minimum power speed vy for a jet aircraft is considerably higher than vy for a propon the thrust curve the best angle of climb speed vx is vmd for a jet and 11vs for a prop derived from the drag curve where the greatest excess of thrust to drag occurs a higher mass will lower the max excess power and thrust and therefore both speeds will increase
exemple 305: Vy and vx are increased
Vx is increased and vy is decreased. vy and vx are not affected by a higher gross mass. vy and vx are decreased.

Question 97-29 : A higher outside air temperature ?

Reduces the angle and the rate of climb.

exemple 309: Reduces the angle and the rate of climb
Increases the angle of climb but decreases the rate of climb. does not have any noticeable effect on climb performance. reduces the angle of climb but increases the rate of climb.

Question 97-30 : When compared to still air conditions a constant headwind component ?

Increases the angle of flight path during climb.

exemple 313: Increases the angle of flight path during climb
Increases the best rate of climb. decreases the angle of climb. increases the maximum endurance.

Question 97-31 : The speed v1 is defined as ?

Take off decision speed.

V1 critical engine failure speed or decision speed engine failure below this speed should result in an aborted takeoff above this speed the takeoff run should be continued
exemple 317: Take off decision speed
Take-off climb speed. speed for best angle of climb. engine failure speed.

Question 97-32 : The speed vlo is defined as ?

Landing gear operating speed.

exemple 321: Landing gear operating speed
Design low operating speed. long distance operating speed. lift off speed.

Question 97-33 : Vx is ?

The speed for best angle of climb.

exemple 325: The speed for best angle of climb
The speed for best rate of climb. the speed for best specific range. the speed for best angle of flight path.

Question 97-34 : The speed for best rate of climb is called ?

Vy.

Vy is the indicated airspeed for best rate of climb climbing at vy allows pilots to maximize the altitude gain per unit timevx is the indicated airspeed for best angle of climb climbing at vx allows pilots to maximize the altitude gain per unit ground distancevx is slower than vy
exemple 329: Vy
Vx. v2. vo.

Question 97-35 : The stalling speed or the minimum steady flight speed at which the aeroplane is controllable in landing configuration is abbreviated as ?

Vso.

Vs is the stalling speed or the minimum steady flight speed at which the aircraft is controllable bottom of the white arc vs0 is the stalling speed or the minimum steady flight speed in the landing configurationvs1 is the stalling speed or the minimum steady flight speed obtained in a specific configuration usually a 'clean' configuration without flaps landing gear and other sources of drag
exemple 333: Vso
Vs1. vs. vmc.

Question 97-36 : The absolute ceiling ?

Is the altitude at which the rate of climb theoretically is zero.

exemple 337: Is the altitude at which the rate of climb theoretically is zero
Can be reached only with minimum steady flight speed. is the altitude at which the best climb gradient attainable is 5%. is the altitude at which the aeroplane reaches a maximum rate of climb of 100 ft/min.

Question 97-37 : The maximum operating altitude for a certain aeroplane with a pressurised cabin ?

Is the highest pressure altitude certified for normal operation.

exemple 341: Is the highest pressure altitude certified for normal operation
Is dependent on aerodynamic ceiling. is dependent on the oat. is only certified for four-engine aeroplanes.

Question 97-38 : The approach climb requirement has been established to ensure ?

Minimum climb gradient in case of a go around with one engine inoperative.

You must be able to perform a go around with one engine inoperative this is the reason why the approach climb requirement has been establishedthe steady gradient of climb may not be less than 24% for two engined aeroplanes 27% for three engined aeroplanes and 30% for four engined aeroplanes
exemple 345: Minimum climb gradient in case of a go around with one engine inoperative
Obstacle clearance in the approach area. manoeuvrability in case of landing with one engine inoperative. manoeuvrability during approach with full flaps and gear down, all engines operating.

Question 97-39 : Which statement relating to a take off from a wet runway is correct ?

A reduction of screen height is allowed in order to reduce weight penalties.

Screen height for take off is the vertical distance between the take off surface and the take off flight path at the end of take off distanceon a wet runway you have to reduce v1 because brake efficiency is reduced this will reduced the max take off weight because in case of failure at v1 the distance on the ground to reach take off speed vr has increasedin that particular case you are allowed to reduce the screen height from 35 ft to 15 ft
exemple 349: A reduction of screen height is allowed in order to reduce weight penalties
The use of a reduced vr is sufficient to maintain the same safety margins as for a dry runway. in the case of a reverser inoperative the wet runway performance information can still be used. screen height reduction cannot be applied because of the consequent reduction in obstacle clearance.

Question 97-40 : Take off performance data for the ambient conditions show the following limitations with flap 10° selected runway limit 5 270 kg obstacle limit 4 630 kgestimated take off mass is 5 000kgconsidering a take off with flaps at ?

5° the obstacle limit is increased but the runway limit decreases.

High flaps selection gives a greater field length limited take off mass but decreases the climb limited and the obstacle limited take off mass because of the reduced climb gradientlow flaps selection gives a reduction of the field length limited take off mass but increases the climb limited and the obstacle limited take off mass because of the improved climb gradienttake off with flaps at 5° will increased the obstacle limited take off mass but will decreased the field length limited take off mass
exemple 353: 5° the obstacle limit is increased but the runway limit decreases
5°, both limitations are increased. 20°, the obstacle limit is increased but the runway limit decreases. 20°, both limitations are increased.



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